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line_in_rectangle_rotated_furthest
Vašek edited this page Feb 10, 2019
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Returns the furthest intersection point of the given line and the given rectangle
line_in_rectangle_rotated_furthest(p1, p2, r)
Argument | Description |
---|---|
Vector2 p1 |
The first point of the given line |
Vector2 p2 |
The other point of the given line |
RotatedRectangle r |
The given rectangle |
Returns: Vector2?
If a given line intersects a given rectangle, the function returns the furthest intersection point. Otherwise, the function returns null.
Vector2 p1 = new Vector2(8, 8);
Vector2 p2 = new Vector2(8, 24);
Vector2 p3 = new Vector2(24, 24);
Vector2 p4 = new Vector2(24, 8);
RotatedRectangle r = new RotatedRectangle(p1, p2, p3, p4);
Vector2? pos = line_in_rectangle_rotated_furthest(new Vector2(0, 0), new Vector2(64, 64), r);
if (pos.HasValue)
{
Vector2 point = pos.Value;
}
This function will set point
to 24, 24.
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