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Create TimSort.java #232

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166 changes: 166 additions & 0 deletions TimSort.java
Original file line number Diff line number Diff line change
@@ -0,0 +1,166 @@
// Java program to perform TimSort.
class GFG
{

static int MIN_MERGE = 32;

public static int minRunLength(int n)
{
assert n >= 0;

// Becomes 1 if any 1 bits are shifted off
int r = 0;
while (n >= MIN_MERGE)
{
r |= (n & 1);
n >>= 1;
}
return n + r;
}

// This function sorts array from left index to
// to right index which is of size atmost RUN
public static void insertionSort(int[] arr, int left,
int right)
{
for (int i = left + 1; i <= right; i++)
{
int temp = arr[i];
int j = i - 1;
while (j >= left && arr[j] > temp)
{
arr[j + 1] = arr[j];
j--;
}
arr[j + 1] = temp;
}
}

// Merge function merges the sorted runs
public static void merge(int[] arr, int l,
int m, int r)
{
// Original array is broken in two parts
// left and right array
int len1 = m - l + 1, len2 = r - m;
int[] left = new int[len1];
int[] right = new int[len2];
for (int x = 0; x < len1; x++)
{
left[x] = arr[l + x];
}
for (int x = 0; x < len2; x++)
{
right[x] = arr[m + 1 + x];
}

int i = 0;
int j = 0;
int k = l;

// After comparing, we merge those two array
// in larger sub array
while (i < len1 && j < len2)
{
if (left[i] <= right[j])
{
arr[k] = left[i];
i++;
}
else {
arr[k] = right[j];
j++;
}
k++;
}

// Copy remaining elements
// of left, if any
while (i < len1)
{
arr[k] = left[i];
k++;
i++;
}

// Copy remaining element
// of right, if any
while (j < len2)
{
arr[k] = right[j];
k++;
j++;
}
}

// Iterative Timsort function to sort the
// array[0...n-1] (similar to merge sort)
public static void timSort(int[] arr, int n)
{
int minRun = minRunLength(MIN_MERGE);

// Sort individual subarrays of size RUN
for (int i = 0; i < n; i += minRun)
{
insertionSort(arr, i,
Math.min((i + MIN_MERGE - 1), (n - 1)));
}

// Start merging from size
// RUN (or 32). It will
// merge to form size 64,
// then 128, 256 and so on
// ....
for (int size = minRun; size < n; size = 2 * size)
{

// Pick starting point
// of left sub array. We
// are going to merge
// arr[left..left+size-1]
// and arr[left+size, left+2*size-1]
// After every merge, we
// increase left by 2*size
for (int left = 0; left < n;
left += 2 * size)
{

// Find ending point of left sub array
// mid+1 is starting point of right sub
// array
int mid = left + size - 1;
int right = Math.min((left + 2 * size - 1),
(n - 1));

// Merge sub array arr[left.....mid] &
// arr[mid+1....right]
if(mid < right)
merge(arr, left, mid, right);
}
}
}

// Utility function to print the Array
public static void printArray(int[] arr, int n)
{
for (int i = 0; i < n; i++) {
System.out.print(arr[i] + " ");
}
System.out.print("\n");
}

// Driver code
public static void main(String[] args)
{
int[] arr = { -2, 7, 15, -14, 0, 15, 0, 7,
-7, -4, -13, 5, 8, -14, 12 };
int n = arr.length;
System.out.println("Given Array is");
printArray(arr, n);

timSort(arr, n);

System.out.println("After Sorting Array is");
printArray(arr, n);
}
}