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Extract types from object literals instead of using the type checker. #60540

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This PR brings TS emit closer to what an external tool could emit without type information by extracting object type directly from their source object literal where possible.

@typescript-bot typescript-bot added the For Uncommitted Bug PR for untriaged, rejected, closed or missing bug label Nov 19, 2024
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This PR doesn't have any linked issues. Please open an issue that references this PR. From there we can discuss and prioritise.

Comment on lines +6163 to +6171
const symbolType = getTypeOfSymbol(symbol);
if (widen) {
type = instantiateType(getWidenedType(symbolType), context.mapper);
}
else {
type = symbol && !(symbol.flags & (SymbolFlags.TypeLiteral | SymbolFlags.Signature))
? instantiateType(getWidenedLiteralType(symbolType), context.mapper)
: errorType;
}
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Seems like this could be just:

Suggested change
const symbolType = getTypeOfSymbol(symbol);
if (widen) {
type = instantiateType(getWidenedType(symbolType), context.mapper);
}
else {
type = symbol && !(symbol.flags & (SymbolFlags.TypeLiteral | SymbolFlags.Signature))
? instantiateType(getWidenedLiteralType(symbolType), context.mapper)
: errorType;
}
type = widen || (symbol && !(symbol.flags & (SymbolFlags.TypeLiteral | SymbolFlags.Signature)))
? instantiateType(getWidenedLiteralType(getTypeOfSymbol(symbol)), context.mapper)
: errorType;

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(the original code with one more expression)

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3 participants