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Add QR algorithm #472
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Add QR algorithm #472
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cd45a97
Replace array_search with floating-point filter
Aweptimum 7c75688
Make 8.2 linter happy
Aweptimum 22ffbbf
Add NumericaMatrix->upperHessenberg
Aweptimum 9fb768a
Test uppserHessenberg
Aweptimum 44637c3
Add qrAlgorithm
Aweptimum 51ba07e
test QRAlgorithm eigenvalues
Aweptimum edb1bb3
Shift QR by Wilkinson, refactor a bit
Aweptimum 51a36e9
Add qr method to Eigenvector
Aweptimum 6b445d9
Test Eigenvector::qrAlgorithm
Aweptimum 2f08e84
Add failing eigenvector cases to eigenvalues
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Question about Hessenberg matrices: Is there only one upper Hessenberg matrix for any matrix, or are there multiple possible Hessenberg matrices that satisfy the critiera?
I tried this test case in R and SciPy and it got a slightly different answer.
R
Python
This online calculator however gets the same answer as you have here.
I'd like to help with generating test cases, but I don't know enough about it so I want to make sure I understand how it works before offering help.
Thanks,
Mark
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I think the values are unique, the signs are not. In addition to the upper hessenberg form, the algorithm also computes a permutation matrix, P, such that
A = PHPT
. Wolfram returns the hessenberg form with the added context of the permutation matrix, and multiplying it accordingly gives the original matrix.In the
NumericMatrix::upperHessenberg
method, the P matrix calculated is exactly the same as R, Python, and Wolfram, it just has different signs:Multiplying
A = PHPT
gives the original matrix as well.So it might be better to return both matrices for context rather than just the upper hessenberg matrix
Also, I had originally tried the other method of getting the matrix in Upper-Hessenberg form using Givens rotations. It seems more widely used than the householder method, and I think that's because it allows for parallelization + works better on sparse matrices. This particular matrix needed (I think) a planar rotation of pi/2 to zero out the 1 at (4, 1), so the givens rotation block was just:
All that to say, I wouldn't be surprised if the Givens method introduced negative signs to both
P
andH