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Add commonPrefix(with:)
, commonSuffix(with:)
#153
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I think it's more natural to not pluralize of |
Fair point. I think I went with this because we already have |
} else { | ||
return nil | ||
} | ||
} |
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I think the iterator needs to add a done
flag to its state. For instance, if we do "1234A56"
vs. "1234B56"
, and we iterate past the first nil
, we'll get a "5"
, instead of nil
forevermore.
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Thanks, you're absolutely right!
by areEquivalent: @escaping (Element, Other.Element) -> Bool | ||
) -> CommonPrefix<Self, Other> { | ||
CommonPrefix(base: self, other: other, areEquivalent: areEquivalent) | ||
} |
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Shouldn't these be using Elements
and elements
instead of Self
and self
?
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That's a way to do it, but this is intentional. If you wrap elements
instead of self
then the type no longer contains any sign of laziness, so you'll need to wrap it in LazySequence<...>
again to add the laziness back. But by wrapping self
, all we need is for CommonPrefix
to conditionally conform to LazySequenceProtocol
when the (first) base collection does, in order to propagate the laziness.
CommonPrefix
also can't unconditionally conform to LazySequenceProtocol
because it's also returned by the Sequence
overloads, so in a non-lazy context.
by areEquivalent: @escaping (Element, Other.Element) -> Bool | ||
) -> CommonPrefix<Self, Other> { | ||
CommonPrefix(base: self, other: other, areEquivalent: areEquivalent) | ||
} |
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Same as in the LazySequenceProtocol
section: shouldn't these be using Elements
and elements
instead of Self
and self
?
Don't |
…ffix` -> `startOfCommonSuffix`
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Find the common prefix/suffix of two sequences or collections.
commonPrefix(with:)
commonSuffix(with:)
endOfCommonPrefix(with:)
: get a pair of indices that mark the end of the common prefix of two collectionsstartOfCommonSuffix(with:)
: get a pair of indices that mark the start of the common suffix of two collectionsChecklist