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是关于自监督损失的复杂度方面的,文中给出的推导过程是 在一个批次的计算中,分子部分:O(Bd) + 分母部分O(BMd) -> 一个批次的总复杂度为 O(|E|d(2+|V|))
关于这个推导不是很理解,目前暂时还没有看源码,所以也不清楚具体的实现是怎么样,我自己的推导过程是 one epoch: user = bd+bmd=b(m+1)d item = bd+bid+b(i+1)d user+item = b(m+2+i)d -> O(bd(2+|V|)) 区别就在 bd(2+|V|) 还是 |E|d(2+|V|) 因为我本人刚入门,可能问题有点蠢,还望您能够解答,文章的其他部分还是能读下来的
The text was updated successfully, but these errors were encountered:
你这边算的是一个mini-batch的计算量,而一个epoch里面有|E|/B个mini-batch,所以总计算量是|E|d(2+|V|)
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不好意思搞混了,谢谢!
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是关于自监督损失的复杂度方面的,文中给出的推导过程是
在一个批次的计算中,分子部分:O(Bd) + 分母部分O(BMd)
-> 一个批次的总复杂度为 O(|E|d(2+|V|))
关于这个推导不是很理解,目前暂时还没有看源码,所以也不清楚具体的实现是怎么样,我自己的推导过程是
one epoch: user = bd+bmd=b(m+1)d item = bd+bid+b(i+1)d
user+item = b(m+2+i)d -> O(bd(2+|V|)) 区别就在 bd(2+|V|) 还是 |E|d(2+|V|)
因为我本人刚入门,可能问题有点蠢,还望您能够解答,文章的其他部分还是能读下来的
The text was updated successfully, but these errors were encountered: