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day_13.py
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day_13.py
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'''
Problem Statement:
Given a binary array, find the maximum length of a contiguous subarray with equal number of 0 and 1.
Example 1:
Input: [0,1]
Output: 2
Explanation: [0, 1] is the longest contiguous subarray with equal number of 0 and 1.
Example 2:
Input: [0,1,0]
Output: 2
Explanation: [0, 1] (or [1, 0]) is a longest contiguous subarray with equal number of 0 and 1.
Note: The length of the given binary array will not exceed 50,000.
'''
# Solution:
class Solution:
def findMaxLength(self, nums: List[int]) -> int:
partial_sum = 0
# table is a dictionary
# key : partial sum value
# value : the left-most index who has the partial sum value
table = { 0: -1}
max_length = 0
for idx, number in enumerate( nums ):
# add 1 for 1
# minus 1 for 0
if number:
partial_sum += 1
else:
partial_sum -= 1
if partial_sum in table:
# we have a subarray with equal number of 0 and 1
# update max length
max_length = max( max_length, ( idx - table[partial_sum] ) )
else:
# update the left-most index for specified partial sum value
table[ partial_sum ] = idx
return max_length