-
Notifications
You must be signed in to change notification settings - Fork 5
/
LC_94_InOrderTraversalBT.cpp
91 lines (76 loc) · 1.98 KB
/
LC_94_InOrderTraversalBT.cpp
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
/*
https://leetcode.com/problems/binary-tree-inorder-traversal/
94. Binary Tree Inorder Traversal
https://practice.geeksforgeeks.org/problems/inorder-traversal-iterative/0/#
*/
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
vector<int> ans1;
void inorder (TreeNode* root)
{
if(!root) return;
inorder(root->left);
ans1.push_back(root->val);
inorder(root->right);
}
class Solution {
public:
vector<int> inorderTraversal(TreeNode* root) {
if(root==nullptr)
return {};
// ans1.clear();
// inorder(root);
// return ans1;
stack<TreeNode*> st;
vector<int> ans;
TreeNode* cur = root;
while(cur || !st.empty())
{
while(cur)
{
st.push(cur);
cur = cur->left;
}
cur = st.top();
ans.push_back(cur->val);
cur = cur->right;
st.pop();
}
return ans;
}
};
vector<int> inorderTraversal(TreeNode* root) {
if(!root)
return {};
stack<TreeNode*> st;
vector<int> ans;
st.push(root);
while(!st.empty())
{
TreeNode* t = st.top();
if(t->left)
{
st.push(t->left);
t->left=nullptr;
continue;
}
ans.push_back(t->val);
st.pop();
if(t->right)
{
st.push(t->right);
t->right = nullptr;
// continue;
}
}
return ans;
}