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GFG_FlatteningALL.cpp
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GFG_FlatteningALL.cpp
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/*
https://practice.geeksforgeeks.org/problems/flattening-a-linked-list/1#
Flattening a Linked List
*/
// { Driver Code Starts
#include <bits/stdc++.h>
struct Node{
int data;
struct Node * next;
struct Node * bottom;
Node(int x){
data = x;
next = NULL;
bottom = NULL;
}
};
using namespace std;
void printList(Node *Node)
{
while (Node != NULL)
{
printf("%d ", Node->data);
Node = Node->bottom;
}
}
Node* flatten (Node* root);
int main(void) {
int t;
cin>>t;
while(t--){
int n,m,flag=1,flag1=1;
struct Node * temp=NULL;
struct Node * head=NULL;
struct Node * pre=NULL;
struct Node * tempB=NULL;
struct Node * preB=NULL;
cin>>n;
int work[n];
for(int i=0;i<n;i++)
cin>>work[i];
for(int i=0;i<n;i++){
m=work[i];
--m;
int data;
scanf("%d",&data);
temp = new Node(data);
temp->next = NULL;
temp->bottom = NULL;
if(flag){
head = temp;
pre = temp;
flag = 0;
flag1 = 1;
}
else{
pre->next = temp;
pre = temp;
flag1 = 1;
}
for(int j=0;j<m;j++){
int temp_data;
scanf("%d",&temp_data);
tempB = new Node(temp_data);
if(flag1){
temp->bottom=tempB;
preB=tempB;
flag1=0;
}
else{
preB->bottom=tempB;
preB=tempB;
}
}
}
Node *fun = head;
Node *fun2=head;
Node* root = flatten(head);
printList(root);
cout<<endl;
}
return 0;
}
// } Driver Code Ends
/* Node structure used in the program
struct Node{
int data;
struct Node * next;
struct Node * bottom;
Node(int x){
data = x;
next = NULL;
bottom = NULL;
}
};
*/
Node* merge(Node* l1, Node* l2)
{
// if(!l1)
// return l2;
// if(!l2)
// return l1;
Node* head = new Node(0);
Node* ptr = head;
while(l1 && l2)
{
if(l1->data < l2->data)
{
ptr->bottom = l1;
l1 = l1->bottom;
}
else
{
ptr->bottom = l2;
l2 = l2->bottom;
}
ptr = ptr->bottom;
}
if(l1)
ptr->bottom = l1;
else
ptr->bottom = l2;
return head->bottom;
}
/* Function which returns the root of
the flattened linked list. */
Node *flatten(Node *root)
{
Node* ptr = root;
while(ptr->next)
{
root = merge(root, ptr->next); // merge this two sorted list
ptr = ptr->next; //we are not changing the next pointer so we can traverse the next list
}
return root;
}