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Prbl122BestTimeToBuyAndSellStockII.java
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Prbl122BestTimeToBuyAndSellStockII.java
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//You are given an array prices where prices[i] is the price of a given stock on
// the ith day.
//
// Find the maximum profit you can achieve. You may complete as many transaction
//s as you like (i.e., buy one and sell one share of the stock multiple times).
//
// Note: You may not engage in multiple transactions simultaneously (i.e., you m
//ust sell the stock before you buy again).
//
//
// Example 1:
//
//
//Input: prices = [7,1,5,3,6,4]
//Output: 7
//Explanation: Buy on day 2 (price = 1) and sell on day 3 (price = 5), profit =
//5-1 = 4.
//Then buy on day 4 (price = 3) and sell on day 5 (price = 6), profit = 6-3 = 3.
//
//
//
// Example 2:
//
//
//Input: prices = [1,2,3,4,5]
//Output: 4
//Explanation: Buy on day 1 (price = 1) and sell on day 5 (price = 5), profit =
//5-1 = 4.
//Note that you cannot buy on day 1, buy on day 2 and sell them later, as you ar
//e engaging multiple transactions at the same time. You must sell before buying a
//gain.
//
//
// Example 3:
//
//
//Input: prices = [7,6,4,3,1]
//Output: 0
//Explanation: In this case, no transaction is done, i.e., max profit = 0.
//
//
//
// Constraints:
//
//
// 1 <= prices.length <= 3 * 104
// 0 <= prices[i] <= 104
//
// Related Topics Array Greedy
// 👍 3950 👎 1952
package leetcode.editor.en;
//java: Best Time to Buy and Sell Stock II
public class Prbl122BestTimeToBuyAndSellStockII {
public static void main(String[] args) {
Solution solution = new Prbl122BestTimeToBuyAndSellStockII().new Solution();
System.out.println(solution.maxProfit(new int[]{1, 7, 2, 3, 6, 7, 6, 7}));
}
//leetcode submit region begin(Prohibit modification and deletion)
class Solution {
public int maxProfit(int[] prices) {
int maxprofit = 0;
for (int i = 1; i < prices.length; i++) {
if (prices[i] > prices[i - 1])
maxprofit += prices[i] - prices[i - 1];
}
return maxprofit;
}
}
//leetcode submit region end(Prohibit modification and deletion)
}