给定一个链表,返回链表开始入环的第一个节点。如果链表无环,则返回 null。
# Definition for singly-linked list.
# class ListNode:
# def __init__(self, x):
# self.val = x
# self.next = None
class Solution:
def detectCycle(self, head: ListNode) -> ListNode:
slow = fast = head
flag = False
while fast and fast.next:
fast = fast.next.next
slow = slow.next
if fast == slow:
flag = True
break
if not flag:
return None
fast = head
while fast != slow:
fast = fast.next
slow = slow.next
return fast