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Algorithm Study

알고리즘 문제 풀이입니다.


Java Run

javac -encoding UTF-8 -d . [path\filename.java]
java [filename]

example

javac -encoding UTF-8 -d . .\SWExpertAcademy\SWEA1204.java
java SWEA1204

List

Operation Example Big-O
Index l[i] O(1)
Store l[i] = 0 O(1)
Length len(l) O(1)
Append l.append(5) O(1)
Pop l.pop() O(1)
Slice list[start:end] O(end-start)
Extend l.extend(...) O(len(...))
Compare list1 == list2 O(N)
Insert list.insert(location, value) O(N)
Delete del list[index] O(N)
Remove list.remove(value) O(N)
Containment target in list O(N)
Copy list.copy() O(N)
value min(list) / max(list) O(N)
Reverse list.reverse() O(N)
Sort list.sort() O(NlogN)

Set

Operation Example Big-O
Length len(s) O(1)
Add s.add(5) O(1)
Containment x in/not in s O(1)
Remove s.remove(..) O(1)
Discard s.discard(..) O(1)
Pop s.pop() O(1)
Clear s.clear() O(1)
Construction set(...) O(len(...))
check ==, != s != t O(len(s))
<=/< s <= t O(len(s))
>=/> s >= t O(len(t))
Union s t
Intersection s & t O(len(s)+len(t))
Difference s - t O(len(s)+len(t))
Symmetric Diff s ^ t O(len(s)+len(t))
Copy s.copy() O(N)

Dictionary

Operation Example Big-O
Index d[k] O(1)
Store d[k] = v O(1)
Length len(d) O(1)
Delete del d[k] O(1)
get/setdefault d.get(k) O(1)
Pop d.pop(k) O(1)
Pop item d.popitem() O(1)
Clear d.clear() O(1)
View d.keys() O(1)
Construction dict(...) O(len(...))