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— divided by the arithmetic mean of the times for C language.
In other words, "the ratio of averages" for each language to the average for C.
As-far-as-I-can-tell that calculation seems to "weight" each program measurement differently.
For example, because the fannkuch-redux programs are run for ~20x more time than the reverse-complement programs; the un-normalized time fannkuch-redux contributes to the average have more weight than the time reverse-complement contributes to the average.
That may be what was intended.
On the other hand, the intention may have been that each program - binary-trees, fannkuch-redux, fasta, reverse-complement - contributed the same weight to the Table 4 average.
If each program was intended to contribute the same weight to the Table 4 average, then Table 4 should show "the average of ratios" ?
I've managed to calculate the exact same "Time" values as those shown in SLE’17 Table 4 : starting from these results tables —
https://sites.google.com/view/energy-efficiency-languages/results
So now I understand those normalized Time values show the arithmetic mean of the times for each language —
(language1 time1 + language1 time2 + language1 time3 + language1 timeN) / N
— divided by the arithmetic mean of the times for C language.
In other words, "the ratio of averages" for each language to the average for C.
For example, because the fannkuch-redux programs are run for ~20x more time than the reverse-complement programs; the un-normalized time fannkuch-redux contributes to the average have more weight than the time reverse-complement contributes to the average.
That may be what was intended.
If each program was intended to contribute the same weight to the Table 4 average, then Table 4 should show "the average of ratios" ?
https://jlmc.medium.com/understanding-three-simple-statistics-for-data-visualizations-2619dbb3677a
https://dl.acm.org/doi/pdf/10.1145/5666.5673
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