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Could I request an abbreviation for the D6 Legends system?
Normally I have to type: /roll [x-1]d6 t4 + 1d6 t4f1ie6
x being the total rolled. So if the check I need to roll is 8 dice, I would have to type '/roll 7d6 t4 + 1d6 t4f1ie6' so that one out of the 8 is the 'Wild Die'. If the wild die is a 1, then 1 is subtracted from the success total, if 2 to 3 is rolled, no success is added, 4 to 5 means one success is added and if a 6 is rolled, one success is added to the total and the die is rolled again. One the subsequent roll of the Wild de, a 1 though 3 means no additional successes are achieved and the rolling stops and successes are calculated. If a roll of 4 to 5 occurs, an additional success is added and the rolling stops and successes are calculated. If a 6 is rolled, an additional success is added and the Wild Die is rolled again following this same results. As long as the 6 is rolled on the Wild Die, rolling continues.
Describe the solution you'd like
An abbreviation of '/roll [x]d6l' that does all that typing above for me. So instead of typing '/roll 7d6 t4 + 1d6 t4f1ie6' I would just type '8d6l'.
The text was updated successfully, but these errors were encountered:
DeviousHearts
changed the title
D6 Legends (aka a d6 success-based with a "wild Die")
D6 Legends (aka a d6 success-based with a "Wild Die")
Jul 7, 2023
Could I request an abbreviation for the D6 Legends system?
Normally I have to type: /roll [x-1]d6 t4 + 1d6 t4f1ie6
x being the total rolled. So if the check I need to roll is 8 dice, I would have to type '/roll 7d6 t4 + 1d6 t4f1ie6' so that one out of the 8 is the 'Wild Die'. If the wild die is a 1, then 1 is subtracted from the success total, if 2 to 3 is rolled, no success is added, 4 to 5 means one success is added and if a 6 is rolled, one success is added to the total and the die is rolled again. One the subsequent roll of the Wild de, a 1 though 3 means no additional successes are achieved and the rolling stops and successes are calculated. If a roll of 4 to 5 occurs, an additional success is added and the rolling stops and successes are calculated. If a 6 is rolled, an additional success is added and the Wild Die is rolled again following this same results. As long as the 6 is rolled on the Wild Die, rolling continues.
Describe the solution you'd like
An abbreviation of '/roll [x]d6l' that does all that typing above for me. So instead of typing '/roll 7d6 t4 + 1d6 t4f1ie6' I would just type '8d6l'.
The text was updated successfully, but these errors were encountered: